We need to learn to slice flat food first. After it is has been deboned, a fish such as salmon is relatively flat.
We are going to make fish sticks, so we need to cut it into thin strips. We slice the fish from top to bottom into nice, even strips. We want them even so the 5yearolds don't get into a fight at the dinner table.
We do the same thing when we break the area under a curve up into rectangular strips. We can use a lefthand sum to approximate the definite integral of a nonnegative function.
If we want to approximate
where "f" stands for fish, we have to know the function f(x) and the interval [a,b]:
We slice up the region between the function and the xaxis into n slices. Each slice has the same width Δ x:
Look at the slice whose left endpoint is at coordinate x:
The area of this slice is approximately the same as the area of the rectangle with width Δ x and height f(x).
The area of the rectangle is
f(x) Δ x.
To approximate the area between f(x) and the x axis on [a,b], we add up the areas of all n rectangles.
If we take the limit of the sum as the number of rectangles n approaches ∞, the intervals Δ x get really small. We get the exact area between f(x) and the xaxis on [a,b]:
In other words, a definite integral is a sum in the limit that we sum over an infinite number of intervals.
We're slicing the region into infinitely many slices of infinitesimal width.
We use dx instead of Δ x for the infinitesimal width because the "change in x" is too small to measure.
Here are a couple review examples to remind us of how to slice areas into vertical intervals.
Our general plan of attack for these problems is pretty straightforward.
1) Figure out the region whose area you're finding. Catch a fish.
2) Slice up the region into strips and find the approximate area of each strip. Make fish sticks.
3) Add up all the approximate areas and take the limit as the number of strips goes to ∞ to get an integral that gives the exact area of the region. Eat an infinite number of fish sticks.
We need to be careful here. While following this plan of attack, there are a few things we need to keep in mind.
We should make sure that we know the region whose area you're finding.
For example, the area of the region between the graph of y = x^{2} and the line y = 1 is this:
Not this:
and not this:
If We don't start with the correct region, we won't find the correct area. It's like trying to find the size of an apple by weighing an elephant. As a first step, it's useful to draw a picture of the region.
We should make sure to know which way we're slicing the region and what our variable of integration means.
Whichever way we slice it, the variable of integration somehow tells the position of a strip. If we slice horizontally, then y tells the position of the strip by giving its distance from the xaxis. If we slice vertically, then x tells the position of the strip by giving its distance from the yaxis. Whenever we finish writing an integral with dy or dx, we should make sure we know what y or x is. Not knowing what our variable of integration means is like trying get a glass of water in the dark at night without our glasses on. We might find what we are looking for, but it'll be mostly by chance.
The limits of integration are whatever values make sense for the variable of integration.
In the last exercise, we found the area of the region between the yaxis, the line y = 2x, and the line y = 2:
If we slice vertically and integrate with respect to x, the limits of integration are 0 to 1 because those are the values that make sense for x. We end up with an integral
If we slice horizontally and integrate with respect to y, then the limits of integration are 0 to 2 because those are the values that make sense for y. In this case, we end up with an integral
What is the area of the shaded region? 
What is the area of the shaded region?

Find the area of the shaded region, using horizontal strips. 
Let R be the shaded region graphed below.
Without using calculus, find the area of R.
Let R be the shaded region graphed below.
Use integration with vertical strips to find the area of R.
Let R be the shaded region graphed below.
Use integration with horizontal strips to find the area of R.