TABLE OF CONTENTS
Solve for the area of a trapezoid with bases of length 4 and 5, with a height of 6.
The area of a trapezoid is always A = ½(b1 + b2)h.
Solve for the area of a trapezoid with bases of length 6 inches and 4 feet, with a height of 6 feet.
Make sure to convert your units (1 foot = 12 inches).
13.5 ft2 or 1,944 in2
Solve for the height of a trapezoid with an area of 24 in2 and bases with lengths of 16 and 8 in.
Rearrange the area equation to solve for h.
A trapezoid with an area of 8 units2 and a height of 4 units has two bases such that one base is three times as long as the other. What are the lengths of the bases?
Plug b1 = x and b2 = 3x into the area of a trapezoid equation.
b1 = 1 and b2 = 3
Solve for the area of the trapezoid below.
Which one of Pythagoras's many theorems should we use to find the height?
The length of the missing base is the small base plus the amount we calculate using the Pythagorean theorem where the hypotenuse is—have we said too much?