At a Glance - Tangents and Secants
Lines and circles tend to avoid each other, because they kind of freak each other out. Lines don't care for the weird curviness a circle has, while circles are mystified by the fact that a line goes on forever and forever and forever...
Anyway, circles and lines don't get along too well, but since they are at the mercy of whoever draws them (to some extent), they do have to interact sometimes.
Throw a line down onto a plane with a circle in it and one of three things will happen. If they are lucky, the line and the circle won't intersect at all. They'll each go about their business, perhaps warily eying each other, but not sharing any points.
You might end up with the line intersecting the circle at two points.
Or, once in a blue moon, you might see the line just "touching" the circle, intersecting it at exactly one point.
We have special names for these last two cases. If a line intersects a circle at two points, then the line is a secant of the circle. If a line intersects a circle at exactly one point, then the line is tangent to the circle. (You can think of a tangent line as just barely touching the circle.)
Suppose line m intersects ⊙X at point Z and m is perpendicular to XZ. What is the maximum number of other points on ⊙X that m can intersect?
Is there a maximum number of secant lines two circles can have in common? If so, what is it? (In other words, given two circles, how many lines m can you draw that m is a secant of both circles?)
In the figure below, segments CA and CB are tangent to ⊙O at points A and B, respectively. If OA = 8 cm and AC = 18 cm, what is the length of BC?
How is it possible for two circles to have only two common tangents?
How is it possible for two circles to have only one common tangent?
A diameter is a secant. True or false?
If a line m is perpendicular to the radius of a circle, then m is not a secant of the circle. True or false?
In the figure below, segments PB and PA are tangent to ⊙O at B and A, respectively. Also, ∠AOB is a right angle. Prove that ∠APB is a right angle.