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Introduction to Computing Derivatives - At A Glance:

Now it's time to throw a monkey wrench into the works, curve ball style. What happens when we mix two variables together, on both sides of the equation? Why calculus? Why?! We're entering the Twilight Zone, we're traveling to another dimension. Once the room stops spinning, we'll move on. Good now? Good. We can handle this.

A function is a special kind of relation where each input has exactly one output. Often we have a rule or a formula that tells us how to reach the input to the output, such as

y = x + 5.

In such cases we say the function is defined explicitly. The dependent variable appears all by itself on one side of the equation, and the other side gives a recipe for making the dependent variable from the independent variable.

We say a function is defined implicitly if we have an equation in which the dependent variable doesn't have a side of the equation all to itself. The equation

5x2 - 4y = 7

is an implicit definition of y, since it doesn't actually say how to go from x to y. If we solve this equation for y we find the explicit definition

We can say that y is "defined implicitly" even if y isn't actually a function. For example, the equation

x2 + y2 = 1

describes a circle of radius 1. A circle isn't a function, since it fails the vertical line test. However, we would still say that this equation implicitly defines y.

For a total headache, we might even say "y is an implicitly defined function" even though y isn't a function. We probably worry about this distinction in class, but we wanted to point it out for the sake of completeness!

Exercise 1

Determine whether y is defined explicitly or implicitly.

  • y = 4x + 3y

Exercise 2

Determine whether y is defined explicitly or implicitly.

  • y = 7x + x2

Exercise 3

Determine whether y is defined explicitly or implicitly.

  • x4 + y = 6y

Exercise 4

Determine whether y is defined explicitly or implicitly.

Exercise 5

Determine whether y is defined explicitly or implicitly.

  • 12x + 16y = x2 - y - 8
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