Use implicit differentiation to find y', assuming that y is a function of x.
Then we move all the y' terms on one side of the equation, so we can solve for y':
What is y' in the following equation?
Then we move all the y' terms on one side of the equation, and we can solve for y':
Using implicit differentiation, what is y ' in the following equation?
Now we move all the y' terms on one side and all the others on the other side:
What is y ' in the following equation?
That denominator of y2 is getting in the way, so multiply both sides by y2. Then we'll be able to solve for y'.
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