Let f (x) = 3x. Find a constant m such that
First we need to know what is. When we look at the graph, we see a trapezoid with heights 6 and 12 and width 2.
The area of this trapezoid is
In order for to be 18 also, m must be 9.
Let f (x) = x. Find a constant m such that
Here's the graph of f (x) = x on [-2,4]:
From this graph we can see that
m(4-(-2)) = 6.
Since (4-(-2)) = 6, We must have m = 1. The weighted area between f (x) = x and the x-axis on [-2,4] is the same as the weighted area between m = 1 and the x-axis on [-2,4].
Find the average value of the function on the specified interval. Check and make sure your answer has the sign you would expect.
The average value of f (x) = x on [-10,0] is
the average value of f (x) = x on [-10,0] is
Since f (x) is below the x-axis on all of [-2,2], it's reassuring that we got a negative number for the average value.
The function on [-2,2] describes half a circle.
The area of this half-circle is
The average of f on [-2,2] is
The average value of f ( x ) = sin x on [-π,π] is
Since sin is an odd function, its integral on [-π,π] is 0. So the average value of f (x) = sin x on [-π, π] is
The graph of f (x) = 3x + 2 on [1,4] describes a trapezoid with width 3 and heights 5 and 14.
The average of f on [1,4] is
The line -2x – 1 hits the x-axis when
so the triangle above the x-axis has base 3.5 and the triangle below the x-axis has base 2.5:
We conclude that the average of f on [-4,2] is
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