Way back in algebra we learned that a solution to an equation is a value of the variable that makes the equation true. This is backwards kind of thinking we need for differential equations.
To check if a number is a solution to an equation, we evaluate the left-hand side of the equation at that number, then evaluate the right-hand side of the equation at that number. If we get the same value for both sides of the equation, the number is a solution to the equation.
Determine if x = 5 is a solution to the equation x^{2} + 6 = 4x + 11. |
Determine if x = 4 is a solution to the equation x^{2} + 6 = 4x + 11. |
Determine whether the function y = x^{2} is a solution to the d.e. xy' = 2y. |
Determine whether the function y = x^{2} + 4 satisfies the d.e. xy' = 2y. |
Show that the function y = xe^{x} is a solution to the d.e. |
Show that y = x ln x is not a solution to the d.e. |
Determine whether y = e^{x} is a solution to the d.e.
y' + y" = 2y.
Determine whether y = xe^{x} is a solution to the d.e.
y' = xy.
Determine whether P = e^{-t} is a solution to the d.e.
Determine whether y = x^{2} is a solution to the d.e.
Determine whether y = x^{n} is a solution to the d.e.
x^{2}y" + ny = n^{2}y.
Show that y = 5x^{2} + 2 is a solution to the d.e.
Show that y = 5x^{2} is not a solution to the d.e.
Show that f (x) = sin x is a solution to the d.e.
f ^{(2)}(x) + f (x) = 0.
Show that f (x) = e^{x}sin x is a solution to the d.e.
2f '(x) - 2f (x) = f (x).
Show that y = ln x is a solution to the d.e.
e^{y} = x^{2}y'.