We can use differential equations to talk about things like how quickly a disease spreads, how fast a population grows, and how fast the temperature of cookies rises in an oven. Translating between English and differential equations takes a bit of practice, but a good starting place is to think "derivative" whenever you see the word "rate."
Make sure you remember what proportionality and inverse proportionality are, because these words come up a lot around differential equations.
Using differential equations to describe real-life situations in this way is called modeling. The differential equation is a model of the real-life situation.
We'd like to take this opportunity to discuss constants and their signs (by which we mean positive and negative, not Capricorn and Sagittarius.
Suppose a population P is increasing at a rate proportional to P. This means

where k is the constant of proportionality. Since the population is increasing, the rate
must be positive. Since the population P will be a positive number, the constant k must also be a {positive number.
Now suppose instead that the population P is decreasing at a rate proportional to P. Since the rate of population change is proportional to P, by the definition of proportionality we have

Since we're told the population is decreasing, its rate of change
must be negative. This means k must be negative, since that's the only way the product kP will turn out negative.
There's another way to write a differential equation for the situation where P is decreasing at a rate proportional to P. We can write

and think of k as positive. Then (-k) is the constant of proportionality. The product of (-k) and P is negative, so the rate
will come out negative like it's supposed to.
Practice:
Translate the following English statement into a differential equation: Jenna's savings account grows at a rate of $300 per year.
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The two quantities described are savings (in $) and time (in years). Let S stand for savings and t for time in years. Then the "rate" at which Jenna's savings account grows is the same thing as the "derivative" of savings with respect to time, or 
The statement says the rate of change of savings is $300 dollars per year. As a differential equation, 
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Translate the following English statement into a differential equation: "The population is increasing at a rate proportional to the size of the population." | |
The statement is talking about the size of a population. Let's use the letter P to refer to the population size. Then the original statement The population is increasing at a rate proportional to the size of the population. becomes the more math-like statement P is increasing at a rate proportional to P. Since population size is a function of time, and this statement doesn't describe any variables besides population size and time, we'll assume that the rate described in the statement is 
where t stands for time. The statement says this rate is proportional to P, which means equal to a constant multiplied by P. So we get this equation: 
where k is the constant of proportionality. | |
Translate the following English statement into a differential equation: The population is increasing at a rate of 2 percent per year. | |
This is similar to the previous problem. Let's use P for population size and t for time in years. It might be tempting to write 
but this is wrong! This would mean the population grows by .02 people per year, which doesn't make any sense. Saying "the population is increasing at a rate of 2 percent" really means "the population is increasing at a rate of 2 percent of the current population," or a rate of 0.02P. The correct differential equation is 
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A population P has a birth rate of 1 percent and 200 people die every year. Find the overall rate of change of the population.
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If the population has a birth rate of 1 percent, its rate of increase is 0.01P. If 200 people die per year, the rate of decrease is 200. To get the overall rate of change , we take the birth rate and subtract off the death rate: 
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Julie makes $200 dollars per week and puts it in her bank account. After making the deposit, she spends 20 percent of the money in her bank account. Model this situation with a differential equation.
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Julie makes $200 dollars per week, so her bank account S increases at a rate of 200. She spends 20 percent of the money, so S decreases at a rate of 0.2S. Her bank account changes at a rate of 
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Translate the English statement into a differential equation. Be sure to specify what your variables are.
The population is increasing at a rate of 1,000 people per year.
Answer
We have a population P and time t measured in years. The population increases at a rate of 1,000 people per year, which means

Translate the English statement into a differential equation. Be sure to specify what your variables are.
The number of bunnies in the forest is increasing at a rate proportional to the number of bunnies there already.
Answer
The two variables are the number of bunnies B and the time t. The statement
The number of bunnies is increasing at a rate proportional to the number of bunnies can be condensed into the statement B is increasing at a rate proportional to B. As a differential equation,

where k is the constant of proportionality.
Translate the English statement into a differential equation. Be sure to specify what your variables are.
Tamara spends $40 per week.
Answer
There are a couple of ways to do this problem. The two variables involved are money M and time t. We know that Tamara's money is decreasing at a rate of $40 dollars per week. If we let t be measured in weeks we get the differential equation

Alternatively, we could calculate that Tamara spends 40 × 52 = 2080 dollars per year, let t be measured in years, and write

In either case, we need the negative sign because Tamara's money is decreasing, meaning the rate of change of her money with respect to time is negative.
Translate the English statement into a differential equation. Be sure to specify what your variables are.
Ben receives 20 pieces of junk mail every day.
Answer
We're looking at the rate of change of J (the number of pieces of junk mail Ben receives) with respect to t (time). It probably makes the most sense to measure time in days, in which casewe get the differential equation

Translate the English statement into a differential equation. Be sure to specify what your variables are.
A batch of cookies is placed in a 375°F oven. The temperature of the cookies increases at a rate proportional to the difference between the temperature of the cookies and the temperature of the oven.
Answer
The variables in question are the temperature of the cookies T (measured in °F) and time t. The original statement
The temperature of the cookies increases at a rate proportional to the difference between the temperature of the cookies and the temperature of the oven
can be simplified:
T increases at a rate proportional to the difference between T and the temperature of the oven.Since we know the temperature of the oven is 375°F, we know that
is proportional to ( T - 375) or ( 365 - T ) (either of these is ok). So the final differential equation can be either

or

The population of bunnies B is increasing at a rate proportional to the size of B. This situation can be modeled with the differential equation

Is the constant k positive or negative?
Answer
Since the population of bunnies B is increasing, the rate of change
must be positive. Since B is positive, k must also be positive so that the product kB is positive.
The population of geese G is decreasing at a rate proportional to G. This situation can be modeled with the differential equation

Is the constant k positive or negative?
Answer
Since the population of geese G is decreasing, the rate of change
must be negative. Since G is positive, in order for the product kG to be negative, k must be negative.
If Q is a positive quantity and

where k < 0, is Q increasing or decreasing?
Answer
If Q is positive and k is negative, then
-kQ = -(negative)(positive)
is positive. This means

is positive, so Q is increasing.
Cookies are placed in a 375°F degree oven to bake. Newton's Law of Heating (link forward) says that the temperature t of the cookies will increase at a rate proportional to the difference between the temperature of the surrounding oven and the temperature of the cookies. If we model this situation by the differential equation

is the constant k positive or negative?
Answer
If cookies are baking, their temperature is increasing, so

must be positive. Since the cookies start out cooler than 375, the quantity (375 - T) is positive. In order for the product k(375 - T) to be positive, k must also be positive.
A hot cup of coffee is placed on the kitchen table in a room that is 68°F. Newton's Law of Cooling (link forward) says that the temperature t of the coffee will decrease at a rate proportional to the difference between the temperature of the surrounding room and the temperature of the coffee. This situation can be modeled by the differential equation

Is the constant k positive or negative?
Answer
If coffee is cooling, its temperature is decreasing, so

must be negative. Since the coffee is warmer than 68° the quantity (68 - T) is negative. In order for the product
k(68 - T)
to be negative, the constant k must be positive.
Some of the problems we've had so far have been way too simplified to be real. People don't just spend $40 per week - in real life, a bank account has some money going in and some money going out.
A population doesn't just increase. In real life, some people are born and some people die.
For most quantities we model with differential equations, we can think of the rate of change in two separate pieces:
- the rate of increase (birth rate, rate of saving)
- the rate of decrease (death rate, rate of spending)
To get the overall rate of change, we combine the rates of increase and decrease:
(overall rate of change) = (rate of increase) - (rate of decrease).
Remember that the units of the derivative are the units of the dependent variable over the units of the independent variable.
Model the situation using a differential equation. State the units of each variable and the units of the derivative.
Water is rushing into a tank at a rate of 5 gallons per minute and rushing out again at a rate of 3 gallons per minute.
Answer
Let W stand for the amount of water in gallons and t for the time in minutes. Then

Model the situation using a differential equation. State the units of each variable and the units of the derivative.
The birth rate of the wolf population is 5 percent per year and hunters kill 200 wolves per year.
Answer
Let W stand for the number of wolves and t stand for time in years. The birth rate is 5 percent of the current population, or .05W. The death rate is 200. Putting it together,

Model the situation using a differential equation. State the units of each variable and the units of the derivative.
Every month Donna's savings account earns 2 percent interest and she deposits an additional $100 dollars.
Answer
Let S be the amount of money in Donna's account and t be time in months. Every month Donna's account gains 2 percent or .02S in interest, and also gains $100. therefore the rate at which her savings account grows is

Since no money is taken out in this problem, we don't need to worry about the rate at which money leaves.
Model the situation using a differential equation. State the units of each variable and the units of the derivative.
A beach is eroding by 10 percent per year. Every month the waves deposit an extra 150 cubic feet of sand.
Answer
Let S be the amount of sand on the beach, measured in cubic feet. Let t be time in years. The rate at which sand accumulates is 150 cubic feet per year. The rate at which sand is carried away is 10 percent of the current amount of sand per year, or .1S. Putting these together,

Model the situation using a differential equation. State the units of each variable and the units of the derivative.
A wasp population has a 10 percent birth rate and a 9 percent death rate. Every year people swat an additional 300 wasps.
Answer
Let W be number of wasps and t be time in years. Then

If we look at the 10 percent birth rate and 9 percent death rate, we see that the wasp population should be increasing by 1 percent per year. Then people swat another 300 wasps per year, so we need to subtract another 300 from the rate.