Improper integrals with badly behaved limits are integrals where one or both of the limits is infinite.
These integrals look like
If only one limit of integration is infinite then the other limit of integration, c, would be a finite constant.
Remember that writing ± ∞ for the limits of integration is a shortcut. These improper integral creatures are really limits.
To evaluate this type of improper integral, we have to work out the integral inside the limit and then evaluate the limit.
When only one of the limits of integration is infinite we can work things out directly. When both limits of integration are infinite we have to split the integral into two pieces first.
There's some weird stuff going on here. If we take a value of p > 1, the integral
converges. But if we take a value of p < 1, that same integral diverges. And the graphs don't even look that different!
Take, for example, p = 2 and :
One way to explain this is that the graph of is able to bound a finite area above the x-axis on [1,∞) because it gets close to zero more quickly than the graph of .
There's another thing going on here we need to point out. Let
Then the function f ( x ) converges to 0 as x approaches ∞. In symbols,
However, the integral
diverges. It's possible for the function to converge to 0 at ∞, but for an improper integral of the function, with an upper limit of ∞, to diverge.
However, if the function f ( x ) diverges at ∞, then there's no hope for the integral
to converge. No matter what c is, if f zooms off to ± ∞ or can't make up its mind what to equal as x approaches ∞, then
is going to diverge.
In fact, if
equals anything other than 0, even if the limit converges, then
will diverge. If then the function and the x-axis will enclose an infinite area on the interval [c,∞).
With the other type of improper integral, it's possible for a function to diverge while the improper integral converges.
Be Careful: When you talk about the convergence or divergence of something, make sure you say what is doing the converging or diverging. Saying that a function converges and saying that an integral converges are not the same thing.
These ideas of convergence and divergence will come up again when we're talking about sequences and series.
So far we've looked at integrals with only one infinite limit. If both limits are infinite, we need to break up the integral somewhere in the middle.
where c is any real number you like (we usually pick something easy like 0 or 1, depending on the function). Since each of the integrals on the right-hand side is really a limit in disguise, this equation says
A sum of limits only exists if both limits involved exist. This is both good news and bad news.
The good news is that if you go to work out
and you find that either
diverges, then you're done. The integral
The bad news is that if
does exist, you have to work out both of the limits
and then add them up. This comes with its own good news, though. You'll already have found the antiderivative for f ( x ) after the first limit, so the second limit won't be as much work.