Show that the point (5,-6) is on the graph of the parametric equations
x = t2 + 1y = 3t
Determine if (5,-6) is on the graph. We know the answer should be "yes". We'll use the y-equation first since we'll find only one t-value that way.
When y = -6 we must have t = -2. Then
x = (-2)2 + 1 = 5.
The point (5,-6) occurs on the graph when t = -2.