One of the first shapes we learn as a toddlers is the circle. It probably didn't take long to realize that pizza is shaped this way. Now we will discuss the unit circle, the circle with radius equal to 1, in terms of pizza.
When we are young, we only eat cheese pizza. Plain, boring, but still delicious, the cheese pizza satisfied every inner desire. Even now, it still sometimes hits the spot.
Next, we learned to relate trigonometric functions to the circle. Sine and cosine became the pepperoni as we add our first pizza topping.
For example, if we erase the arrows that give direction and the labels that say which values of t go with which points, the following three parameterizations all produce the pepperoni unit circle:
- The normal parameterization
x(t) = cos t
y(t) = sin t
for 0 ≤ t ≤ 2π.
This parameterization starts at the point (1,0) when t = 0 and travels the unit circle once in a counterclockwise direction.
- This starts at the point (-1,0) and travels the unit circle once in a counterclockwise direction.
- The graph of the parametric equations

- for 0 ≤ t ≤ 8π.
- This starts at the point (1,0) and travels the unit circle twice in a counterclockwise direction.
If we erase the arrows and the labels that say what values of t belong to which points, we can't tell the difference between these two graphs. They both look like this:

If the graph doesn't have labels and arrows, we can't tell how quickly or how many times the circle is traced. We also doen't know where the stylus started.
All we can see is the circle. Put another way, it's still a pizza.
Now that we are a little older, our tastes have refined, and we prefer other pizza toppings. We invite our friends over for a pizza dinner, but no three people can agree on a topping set. Fortunately, there are infinitely choices of pizza toppings, and these are unit pizzas, they are small enough for everyone to have their own. Each different set of toppings changes the way a pizza tastes.
Similarly, there are infinitely many parameterizations of the unit circle. Different parameterizations may affect
- the starting point on the circle,
- the speed at which the circle is drawn,
- how many times the circle is traced, and
- whether the circle is drawn clockwise or counterclockwise.
A typical parameterization of the unit circle is
x(t) = cos t
y(t) = sin t
for 0 ≤ t ≤ 2π.
We can tweak this to find new parameterizations that meet certain criteria.
Practice:
Give a parameterization of the unit circle that starts at the point (1,0) and draws the unit circle once in a clockwise direction for 0 ≤ t ≤ 2π.
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With the labels and arrows, we're trying to find this graph: 
We want the etch-a-sketch stylus to start at the same point and travel the same speed as usual, but we want it to travel the opposite direction. What does that mean? When we don't want the stylus to be at . We want it to be at .  When } we don't want the stylus to be at (0,1). We want it to be at (0, -1).
 To summarize, we want the y-coordinates to be negative, and the x-coordinates to remain unchanged.
 We want to stick a negative sign in front of the y equation, and leave the equation for x unchanged. Our new parameterization is
x(t) = cos t y(t) = -sin t for 0 ≤ t≤ 2π. | |
Give parametric equations and bounds for the parameter that traces the unit circle clockwise so that the etch-a-sketch stylus is at (0,1) when t = 0 and again when t = π. This is a sausage pizza because it's made from the same stuff as pepperoni but tastes different.
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We want to get this circle:
 Start with the "usual" parameterization and mess with it until we find what we want. In the "usual" case, x goes from 1 to -1 then back to 1: draw circle and highlight where x is on x axis as drawing and y goes from 0 to 1, down to -1, then back up to 0: To draw the unit circle as specified in the problem, we want to have x go from 0 to 1, down to -1, then back to 0: and we can have y to go from 1 to -1 then back to 1: It looks like we want x to do what y does in the "usual" parameterization, and we want y to do what x does in the parameterization. Switch the equations: x(t) = sin t y(t) = cos t Use a graphing calculator to see what happens. We're tracing out the unit circle starting at the right place: The one thing we need to resolve is that the stylus is moving too slowly. We're supposed to travel all the way around the circle as t goes from 0 to π. Right now it's taking us from t = 0 to t = 2π to draw the whole circle. Cut the period of the equations in half, taking x(t) = sin (2t) y(t) = cos (2t) for 0 ≤ t ≤ π. Now we have what we want: To check the answer for a problem like this, stick the equations and the bounds for the parameter in a calculator. See if we find the correct graph, drawn in the correct direction. If the calculator draws the graph too quickly to see what direction it's going, play with the bounds for the parameter. If we graph the normal unit circle for 0 ≤ t≤ π and then for 0 ≤ t≤ 3π/2, we can see that the unit circle is traced in a counterclockwise direction. | |
Give parametric equations and bounds for the parameter that describe the unit circle as shown. In each case the unit circle should be traced only once. Check the answers by putting them in a calculator and seeing if we find the right picture.
Answer
- We want to trace the unit circle starting from the usual point and going in the same direction as usual. However, we want to trace it very slowly, taking 8π to go around instead of 2π. Take the usual parameterization and make the period of each equation 4 times longer:
- Since we want to take 8π to go around the full circle, we need0≤ t ≤ 8π.
Give parametric equations and bounds for the parameter that describe the unit circle as shown. In each case the unit circle should be traced only once. Check the answers by putting them in a calculator and seeing if we find the right picture.
Answer
- We want to start at (-1,0) and go around the circle clockwise. The value of y will be doing the same thing it always does: going from 0 up to 1, down to -1, then back up to 0.

We can leave the equation for y unchanged.
The value of x usually goes from 1 to -1 and back to 1. 
Instead, we want to go from -1 to 1 and back to -1. 
That is, we want x to be the negative of what it usually is. We need to stick a negative sign on the front of the equation for x.
The new parameterization isx(t) = -cos ty(t) = sin t.Since we're going around the circle at the normal speed, we have0≤ t ≤ 2π.
Give parametric equations and bounds for the parameter that describe the unit circle as shown. In each case the unit circle should be traced only once. Check the answers by putting them in a calculator and seeing if we find the right picture.
Answer
- We want to start at (0,1) and go around the circle counterclockwise from t = 0 to t = 4π.
From this example we know that switching the "normal" equations traces out the circle clockwise startingfrom (0,1).
x(t)& = &sin ty(t)& = &cos t
0≤ t ≤ 2πPICTURE param eq 23Start with these equations. We want y to stay the same, moving from 1 down to $-1 and back up to $1:PICTURE param eq 24However, we want x to be the opposite. We want x to first move to $-1, then to $ + 1, then back to 0:PICTURE param eq 25If we stick a negative sign in front of the x equation and leave the y equation unchanged, we'll draw the circle in the correct direction. The equations
x(t) = -sin ty(t) = cos t
for 0 ≤ t ≤ 2πproduce the circle starting at the correct point and drawn in the correct direction:PICTURE graph these, with arrows and label t = 0 and t = 2πThere's one thing left to address: the speed. Right now we're taking from 0 to $2π$ to draw the circle. That's not long enough. We want to take from 0 to 4π. Tofix this, double the period of each equation. The final parameterization is
x(t) = -sin (\frac{t}{2})y(t) = cos (\frac{t}{2})
for 0 ≤ t ≤ 4π.