- Topics At a Glance
- Functions
- Increasing or Decreasing or...
- Bounded
- Even and Odd Functions
**Vectors: A New Kind of Animal**- Magnitude
- Direction
**Scaling Vectors**- Unit Vectors
- Vector Notation
- (More than 2)-Dimensional Vectors
- Vector Functions
- Sketching Vector Functions
- Parametric Equations
- Graphing Parametric Equations
- Points on Graphs of Parametric Equations
- Parametrizations of the Unit Circle
- Parameterization of Lines
- Polar Coordinates
- Simple Polar Inequalities
- Switching Coordinates
- Translating Equations and Inequalities between Coordinate Systems
- Polar Functions
- Graphing Polar Functions
- Rules of Graphing We Do (or Don't) Have
- Bounds on Theta
- Intersections of Polar Functions
- In the Real World
- I Like Abstract Stuff; Why Should I Care?
- How to Solve a Math Problem

Quiz time. Already? Yep.

What's one apple plus another apple? Two apples.

What's two oranges less one orange? One orange.

What's one griffin plus one minotaur? Any mythology buff could tell you it's a griffotaur, of course.

Adding and subtracting vectors is something like adding the griffin and the minotaur. It's possible to add two vectors together or subtract one vector from another. We get another vector in its place. To add vectors, we add the *x*-components to each other and add the *y*-components to each other.

To add the vectors <3, 4> and < 5, 6> we add the first components together and add the second components together:< 3, 4> + < 5,6> = <8, 10>.

To subtract, we subtract the *x*-components and then subtract the *y*-components.

<3,4>-<5,6> = <-2,-2>.

When we add or subtract vectors, remember to deal with the *x*-components and the *y*-components separately. Why? Going back to counting fruit, apples are the *x*-component and oranges are the *y*-component of vectors. We can't add apples to oranges, but we can add apples to apples and oranges to oranges.

Now we're going to work with multiplication of a vector by a real number. To multiply a vector by a number, we multiply each component of the vector by that number.

Multiply the minotaur vector by 2. What do we get? A minotaur twice the size. Likewise, if we multiply the griffin by 0.01, we get a pint-sized, cute griffin to take home with us.

When we multiply a vector by a real number, we call the number a **scalar**.

We call the real number a scalar because it *scales* the vector to be a different size. If the scalar is negative it will also change the direction of the vector.

Take the vector <1,2>. This vector has magnitude √5:

Now multiply the vector by 3 to get a new vector: <1, 2> => <3, 6>.The magnitude of the new vector is

The original vector <1,2> had magnitude √5, The magnitude of the new vector <3, 6> is 3 times greater than the magnitude of the original vector <1, 2>. In multiplying the vector by 3, we scaled the arrow to be 3 times longer.

Example 1

Multiply the vector <9, 2> by 5. |

Example 2

What is the magnitude of the vector 5<2,3>? |

Example 3

If the vector a<4,3> has magnitude 10, what is |

Example 4

By what number must we multiply the vector <3,5 > to get a vector of length 2? |

Example 5

What happens to the magnitude and direction of the vector <2,2> when it is multiplied by -1 ? |

Exercise 1

Perform each vector operation.

- <2,-10> + <4,6>

Exercise 2

Perform each vector operation.

- <3,7 > + <-2,-3>

Exercise 3

Perform each vector operation.

- <1,1> -< -3,-6>

Exercise 4

Perform each vector operation.

- <2,2> + <1,5>

Exercise 5

Perform each vector operation.

- <11,0.3> -<1,0.4>

Exercise 6

Work out each multiplication problem.

- 7<3,4>

Exercise 7

Work out each multiplication problem.

- 2<2,8>

Exercise 8

Work out each multiplication problem.

- -5<-3,-7>

Exercise 8

Work out the multiplication problem.

4/3 <6,-1>

Exercise 9

Work out each multiplication problem.

- -3<6,-1>

Exercise 10

Work out each multiplication problem.

- 0<7,6>

Exercise 11

- Find ||3<7,10>||.

Exercise 12

- A vector
*v*has magnitude 10. What is the magnitude of the vector ?

Exercise 13

- If the vector
*a*<5,12> has magnitude 39, what is*a*?

Exercise 14

- Find the magnitude of the vector (-1)<8,3>.

Exercise 15

- Find the magnitude of the vector (-2)<3,2>.