You've enjoyed your slice of pie, and you've even gone back for seconds while nobody was watching. You need to pack the rest into a box and take it with you to share. You can only find square-shaped boxes, how do you know you the last 2/3 of the pie is going to fit into a box?
We need to have a way to translate from polar to rectangular coordinates and vice versa. This is no problem, since we can describe where a point is using either polar or rectangular coordinates, and we only need a few tools to switch between coordinate systems.
We'll start with points in the first quadrant. Any point in the first quadrant can be described by rectangular coordinates
(x,y) where x,y≥ 0 or by polar coordinates
(r,θ) where r≥ 0 and 
To translate between coordinate systems, draw a right triangle whose hypotenuse connects the origin and the point. One leg of the triangle should be on the x-axis.

The rectangular coordinates tell us the lengths of the legs of the triangle:

The polar coordinates tell us the hypotenuse and one angle of the triangle (since it's a right triangle, we know all the angles):

Each set of coordinates is telling us different information about this triangle. We can use one set of coordinates and a small selection of our tools for solving triangles
to find the other set of coordinates.
Going from rectangular to polar coordinates is the same thing as finding the magnitude and direction of a vector.
To go from polar to rectangular coordinates, remember the definitions of the sine and cosine functions (links to sine and cosine).
It's a little trickier to translate between coordinates when the points are in other quadrants.
The first thing we do, no matter which way we're translating, is recognize which quadrant the point is in. After translating between coordinates, the point should still be in the same quadrant. This will help us know if our answer is reasonable.
To go from rectangular to polar coordinates is still the same thing as finding the magnitude and direction of a vector. To find the direction we may need to use a reference angle.
To go from polar to rectangular coordinates, we don't need to worry about reference angles. All we need to do is use the definitions of sin and cos.
Translating points between rectangular and polar coordinates may be a bit tedious. Going from rectangular to polar coordinates is the same thing as
finding the magnitude and direction of a vector. Going from polar to rectangular coordinates means plugging values into the formulas
x=rcos θ
y = rsinθ
Also, if the point in question lies on the x- or y-axis, there's no need for fancy formulas. We can translate visually.
Practice:
The rectangular coordinates of the point P are (4,3). What are the polar coordinates of this point?
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Graph the point P and draw the triangle:  We need to find r and θ. We use the Pythagorean theorem to find the hypotenuse:  To find θ we use the definition of the tangent function. 
Therefore
 The polar coordinates of P are (r,θ) = (5, .644). 
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The polar coordinates of the point Q are What are the rectangular coordinates of Q?
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Graph the point Q and draw the triangle: 
We need to find x and y. To find y we use the definition 
to find 
Therefore
 To find x we use the definition 
to find 
Therefore 
The rectangular coordinates of Q are 

If the point in question is on one of the axes, there's no need to draw a triangle because we can look and see what's going on. | |
What are the polar coordinates of the point with rectangular coordinates (5,0)?
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The point lies on the x-axis: 
Since the point is on the positive side of the x-axis, we can take θ = 0. Since the point is a distance of 5 from the origin, r must be 5. The polar coordinates are
(r,θ) = (5,0).
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Translate the rectangular coordinates (-4,-4) into polar coordinates.
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This point is in the third quadrant: 
When we translate into polar coordinates, r should be positive and θ should be between π and  Here's the useful triangle:  We find the magnitude r by finding the hypotenuse of the useful triangle:

Then we find the direction θ by finding the reference angle α and adding π: 
We have
 therefore 
The polar representation of the point is 
This is in the correct quadrant, it's a reasonable answer. | |
Translate the polar coordinates into rectangular coordinates.
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This point is in the fourth quadrant, which means the rectangular coordinates should have x>0 and y<0. 
We know that 
We do mean θ here, not some reference angle. 
Therefore y = rsin θ. Similarly, x = rcos θ. To find x and y, we plug the values and into these equations. 
The rectangular coordinates are 
This point is in the correct quadrant, it's a reasonable answer. | |
- Convert each set of rectangular coordinates to polar coordinates.

- (1,1)

- \item Translate each set of rectangular coordinates into polar coordinates.



- (0,-5)
Answer
- To translate into polar coordinates we need to find the magnitude r and direction θ of the vector with the given components.
- This point, or vector, is in the third quadrant.The magnitude is

The direction is
.
The polar coordinates are

These coordinates describe a point in the third quadrant, this is a reasonable answer.
- This point is in the second quadrant.
- The magnitude is

The direction is
.
The polar coordinates are

These coordinates still describe a point in the second quadrant, this is a reasonable answer.
- This point is in the fourth quadrant. The magnitude is

The direction is
.
The polar coordinates are

This describes a point in the fourth quadrant, this is a reasonable answer.
- The point (0,-5) lies on the negative y-axis.We can see that its magnitude is 5 and its direction is 3π/2, its polar coordinates are
.
- Translate each set of polar coordinates into rectangular coordinates.



- (4,π)
Answer
- To translate into rectangular coordinates we apply the formulas x = rcosθ and y = rsinθ.
- The point
is in the second quadrant.


The rectangular coordinates are

which do indeed describe a point in the second quadrant.
- The point
lies in the third quadrant.


The rectangular coordinates are

which do describe a point in the third quadrant.
- The point
is in the third quadrant.


The rectangular coordinates are 
which are indeed in the third quadrant.
- The point (4,π) is on the negative x-axis.
- We don't need to bother with formulas because we can see immediately that the rectangular coordinates of this point are(x,y) = (-4,0).