Think you’ve got your head wrapped around **Polynomials**? Put your knowledge to
the test. Good luck — the Stickman is counting on you!

Q. Which of the following is *not* a polynomial equation?

5*x*^{3} - 7*x* + 9 = 3*x*^{4} + 2*x* + 7

3*x*^{2} + 8 = 0

4*x*^{8}-6*x*^{-1} = 0

11*x*(4*x* - 17) = 0

2*x*^{7} + *x* - 4 = 0

Q. The polynomial (*abc*)^{2} - 100*b*^{4} factors completely as

(*abc* + 10*b*^{2})^{2}

(*abc* - 10*b*^{2})(*abc* + 10*b*^{2})

(*abc* - 10*b*^{2})^{2}

Q. Factor the polynomial -6*x*^{2} + 53*x* - 40.

(-3*x* + 20)(2*x* - 2)

(3*x* - 4)(-2*x* + 10)

(-6*x* + 5)(*x* - 8)

(-*x* + 10)(6*x* - 4)

(2*x* - 4)(6*x* + 9)

Q. Which of the following polynomials is *not* a factor of -2*x*^{5} - *x*^{4} + 21*x*^{3}?

(2*x* + 7)

(-*x* + 3)

(*x* + 3)

Q. Factor the polynomial 25*x*^{2} - 30*xy* + 9*y*^{2}.

(5*x* - 3*y*)^{2}

-(5*x* + 3*y*)^{2}

(5*x* + 3*y*)(5*x* - 3*y*)

(-5*x* - 3*y*)^{2}

(-5*x* + 3*y*)(5*x* + 3*y*)

Q. If (3*x* + *a*)(-*x* + *b*) = -3*x*^{2} + 2*x* + 40, what are *a* and *b*?

Blood types

Q. What polynomial has roots 3, 5, and -7?

(*x* + 3)(*x* + 5)(*x*-7)

(*x*-3)(*x* - 5)(*x* + 7)

(*x* + 3)(*x* + 5)(7 - *x*)

(*x* - 3)(*x* - 5)(7 - *x*)

Who are we to dig into a polynomial's personal business?

Q. To factor 12*x*^{2} + 17*x* + 6 by grouping, we should first rewrite the polynomial as

12*x*^{2} + 3*x* + 24*x* + 6

12*x*^{2} + 8*x* + 9*x* + 6

12*x*^{2} + 14*x* + 3*x* + 6

12*x*^{2} + 15*x* + 2*x* + 6

12*x*^{2} + 11*x* + 6

Q. Which of the following polynomial equations has no real number solutions?

-*x*^{3} = 27

4*x*^{2} - 36*x* + 81 = 0

3*x* = 4*x* + 1

Q. Find the roots of the polynomial -*x*^{3} + 9*x*^{2} - 20*x*.

0, 4, 5

0, -4, -5

0, -4, 5

0, 4, -5

0, 3, -3