We sort of gave away the answer with the wording of this problem. Oops. We have a problem with that. If you haven't seen *The Usual Suspects*, you should steer clear of us. We will *definitely* blow the ending for you. It isn't possible to factor this polynomial, but why not? If we could factor the polynomial as (*x *+ *m*)(*x* + *n*), we would need *mn *= 9 and *m *+ *n* = 8. There aren't two integers that multiply together to give 9 and add together to give 8. We tried everything; we even took out an ad in the paper, but no luck: 1 and 9 don't work; 3 and 3 don't work; -1 and -9 don't work; -3 and -3 don't work. There aren't any pairs of numbers left to try that multiply to give 9, so we can't factor the polynomial. Now we're out $25 for that ad. |