This polynomial isn't quadratic. However, all the terms have a common factor of 2*x*. Let's take that out and see what happens. First: (2*x*)(*x*^{2} - 4*x* + 3). The second factor *is* quadratic. Can we factor it further? We need two numbers whose product is 3 and whose sum is -4. Hey, we happen to know the two numbers that will fit the bill. -3 and -1 work, so we can factor the original polynomial as (2*x*)(*x* - 3)(*x* - 1). Remember, you can always check your answer to a factoring problem by multiplying out the factors. The product of the factors should be the original polynomial. If it isn't, you've gone wrong somewhere. Maybe you took a wrong turn at Algebraquerque. |