The two events here are A: rolling 2 on the first die B: rolling 3 on the second die. These events are *not* mutually exclusive. We can roll 2 on the first die and 3 on the second die at the same time. We've done it before, and we shall live to see it happen again. We can find the probability that at least one of the events A or B happens by looking at the table: If we roll 2 on the first die, 3 on the second die, or both (2 on the first and 3 on the second at the same time), then (at least) one of events A and B has happened. "At least one" is good enough for us. We're easy. There are 11 favorable outcomes where A or B happens, out of 36 total outcomes. So the probability of rolling 2 on the first die or 3 on the second die (or both) is . If instead we try to add the probabilities of the two events, we find which is wrong. Close, but wrong. Like Mapquest directions. |