How many real number or complex number roots does the following equation have?

y = x^{2} + 4x + 1

There's an easier way to find out than going through the trouble of finding all the roots yourself.

Let's use the discriminate! b^{2} – 4ac.

Er…we might need to know what a, b, and c are first.

a = 1b = 4c = 1

16 – 4(1)(1) = 16 – 4 = 12

The discriminate is positive, so there are two real number roots for this equation.