How many real number or complex number roots does the following equation have?
y = x2 + 4x + 1
There's an easier way to find out than going through the trouble of finding all the roots yourself.
Let's use the discriminate! b2 – 4ac.
Er…we might need to know what a, b, and c are first.
a = 1b = 4c = 1
16 – 4(1)(1) = 16 – 4 = 12
The discriminate is positive, so there are two real number roots for this equation.