Find the global max and global min of the function on the specified interval.
f (x) = x2 + 3x on the interval [-2,3]
The derivative is
f'(x) = 2x + 3
which is zero when x = -3/2.
We evaluate f at this critcial point and at the endpoints:
On the specified interval, the global max of f is y = 18 and the global min of f is y = -2.25.