Find the global max and global min of the function on the specified interval.
f (x) = sin x on the interval [π,2π]
The derivative of f is f'(x) = cos x, whose only root on the given interval occurs at .
We evaluate f at the critical point and at the endpoints of the interval:
The global max of f on this interval is y = 0 (which occurs at two different values of x) and the global min is y = -1.