Find the global max and global min of the function on the specified interval.
The derivative is f'(x) = x2 + 3x - 10, which factors as
f'(x) = (x + 5)(x - 2).
The critical points occur at x = -5 and at x = 2.
We evaluate f at the critical points and at the endpoints of the interval:
The global max is y = 46.5 and the global min is .