Find where the global max and global min of the function occur (on the specified interval).
f (x) = 2x2 + 3x - 2 on the interval [-2,2]
The derivative is
f'(x) = 4x + 3
which is zero when , so this is our critical point.
We evaluate f at all the important places:
The global max of f occurs when x = 2 and the global min when .