# Sequences and Series

Geometric Sequences

# Geometric Sequences

It is our experience that people tend to wig out by the time they to geometric sequences. Shmoop to the rescue. What else is new? All you need to remember is that while arithmetic sequences add to get the next number in the sequence, geometric sequences multiply.

That means that this is a geometric sequence:

4, 8, 16, 32, 64, …

In that sequence we are multiplying by 2 each time. This means that 2 is called the common ratio.

The common ratio in that geometric sequence is . Your turn.

### Sample Problem

Find the common ratio for the sequence given by

Solution: Remember, the common ratio is just the number we multiply by to get to the next number in a geometric sequence. Here, our numbers are getting smaller. Instead of multiplying by a whole number, we're going to have to multiply by a fraction. This is a completely normal thing for geometric sequences by the way. Here, it is fairly easy to see that we're multiplying by ½.
The other thing it might be helpful to know at this point is the general form of a geometric sequence. It looks like this:

{an} = a1(r)n-1

This means that the nth term, an, is just the first term multiplying by the common ratio, r, to the nth power. You're probably going to want to commit that general form equation thingy right there to memory. It will be worth it.

### Sample Problem

List the first four terms and the 20th term of a geometric sequence with a first term of 1 and a common ratio of 2.

Solution: Let's first find our rule for this thing and then use it to get our terms. Since a1 = 1 and r = 2 we can substitute to get…

an = a1(r)n-1an = 1(2)n-1

Now we can find our first four terms and even our 20th term pretty easily.

a1= 1(2)1-1 = 1(2)0 = 1(1) = 1
a
2= 1(2)2-1 = 1(2)1 = 1(2) = 2
a
3= 1(2)3-1 = 1(2)2 = 1(4) = 4
a4= 1(2)4-1 = 1(2)3 = 1(8) = 8…
a20= 1(2)20-1 = 1(2)19 = 1(1) = 524,288

So our sequence looks like 1, 2, 4, 8,…,524,288,…S, Double U, Double E, T.

Oh, and just one thing worth noting in that example. Notice how the first term ended up with a common ratio to the power of zero. This is exactly what allows our general form to work. Since any number to the zero is just one, it means our first term will always be a1 times one. This is just a1—every single time.

### Sample Problem

Use the geometric sequence given by to find the 5th and 10th terms.

Solution: Oh no. Not the 10th term…You can just go ahead and use the formula on this one.

Wow, that's really small. But that also should make sense since the bigger n gets, the smaller the corresponding term will be. We say that the term approaches zero as n approaches infinity. Whoa—calculus.

### Sample Problem

Find the rule for the geometric sequence with a1 = 6 and .

Solution: Finally, a problem we sink our Shmathematical teeth into. Let's start with what we know. Since a1 = 6 we know that the general form needs to look like…

an = 6(r)n-1

We also know that a4 = . By substituting 4 for n and for a4 we could solve for r.