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Liana runs 0.25 miles on January 1st. She runs 0.5 miles farther each day.
How far does Liana run on January 8th?
What is the first day on which Liana runs 5 miles?
This story problem describes an arithmetic sequence where n is the day in January and an is how many miles Liana runs that day.
The first term is how many miles Liana runs on the first day:
a1 = 0.25
The difference is the number of miles by which she increases her run each day:
d = 0.5
Since this is an arithmetic sequence, the nth term is
an = a1 + (n – 1)d.
This is the distance Liana runs on the nth day in January.
1. On January 8th, the 8th day of January, Liana runs a8 miles. We use the formula to find a8.
a8 = a1 + (7)d
= 0.25 + (7)(0.5)
On the 8th day of January, Liana runs 3.75 miles.
2. We want to know the first day on which Liana runs 5 miles. This means we want to know the smallest value of n for which
an ≥ 5.
Using the formula for an arithmetic sequence, we want to know for which n we first have
a1 + (n – 1)d ≥ 5
We put in the values of a1 and d and solve the inequality:
0.25 + (n – 1)(.5) ≥ 5
(n – 1)(.5) ≥ 4.75
n – 1 ≥ 9.5
n ≥ 10.5
A sequence doesn't have a 10.5th term, so that can't be the right answer. Let's find a10 and a11 and see which is a better choice.
a10 = 0.25 + (9)(.5) = 4.75
a11 = 0.25 + (10)(.5) = 5.25
On January 10th Liana runs 4.75 miles, so she didn't run 5 miles that day. On January 11th she ran more than 5 miles. January 11th is the first day she runs 5 miles.
The best advice we can give for story problems is to write out the first few terms of the sequence so you can see the pattern. Like avoiding brain freeze from eating ice cream too fast, the only way to get better is to practice.