We have an entire tool belt full of convergence tests to determine if series converge or diverge. The tests are as diverse as tools on a tool belt, too. The divergence test is a drill to bore holes into a series we suspect diverges, and the comparison test is a tape measure for us to compare to other series. We can even use the relationships of absolute and conditional convergence like a hacksaw to cut a series in half using the absolute value to check for absolute convergence. Tim "The Tool Man" Taylor would approve.
Now that we have all of the these fancy tools hanging around our waist, we need to now which tools to use when. It takes a bit of a mental jump to go from problems that say
"use the ratio test to determine if this series converges"
to problems that say
"determine if this series converges"
without giving any hints about which test(s) you should be using.
We presented the tests more-or-less in the order you should try them.
- Try the divergence test. It's easy to check if the terms of a series converge to 0. If they don't, you know the series diverges and you don't have to do any more work. Almost as easy, is the series a geometric series? If so, is |r| < 1?
- Is the series an alternating series? If so, try the AST.
- Try the integral or ratio test, depending on what the terms look like. It probably won't make sense to try both the integral test and the ratio test.
(a) If it looks like the ratio
will simplify nicely, try the ratio test. Exponents and factorials are good indicators.
(b) If it looks like the terms are given by an integrable function, try the integral test.
- The comparison test is the only one left, so try that. You may also need to use some other test to show the convergence/divergence of the series you're using for comparison.
- One other idea to have in the back of your head: if the series converges absolutely, then the series converges. If the divergence test and AST don't help, you might want to ask yourself if showing absolute convergence is the easiest way out.
Just like woodworking or machining a widget, the best way to get better is to practice. Learning to use the right tools can be frustrating in any situation. We should keep that in mind, being grateful that these aren't real power tools. We can't cut a thumb off using the alternating series test.
There are multiple right ways to solve most of these problems. If you use a way we didn't mention, check with someone else to see if you found another correct way.
Practice:
Determine if the series converges or diverges.

Answer
Since

the divergence test says this series diverges.
Determine if the series converges or diverges.

Answer
The divergence test is no help. The limit of the terms is zero:

This means there's hope for the series to converge and we need to try another test. This isn't a geometric series or an alternating series, it doesn't look like an integrable function, and it doesn't look very ratio-like (no exponents or factorials). That leaves the comparison test.
Since the denominator has a 3n we guess the series converges. We need to find a series with bigger terms that also converges. Thankfully, since making the denominator smaller makes the fraction bigger,

(we should point out that everything in sight is positive, so the required condition that the terms be non-negative is met). The series

converges (it's a geometric series with |r| < 1, or you could use the ratio test if you really wanted). This means the smaller series

also converges.
Determine if the series converges or diverges.

Answer
Even though this really looks like a ratio test series, remember to try the divergence test first.
The formula for the nth term simplifies to

Now we can see that as n goes to infinity, the value of the nth term approaches
. Since the terms don't converge to zero, the series diverges.
While we could use the ratio test, it's horrible and messy unless we simplify the terms first. And if we're going to simplify the terms anyway, we may as well use the divergence test.
Determine if the series converges or diverges.

Answer
We try the divergence test first. Since the terms approach zero, all the divergence test tells us is that this series might converge.
It's not a geometric series or an alternating series. This looks like an integrable function, so integrate:

Since the function
is non-negative and decreasing on [1,∞), and its integral diverges, the series diverges too.
What about the two tests we didn't use? Could we have used either of them?
- We can't use the ratio test:
so the ratio test tells us nothing. - We can't use the comparison test: making the denominator smaller makes the fraction bigger, so
Since the harmonic series diverges, this comparison goes the wrong way. There aren't any other obvious series to compare to.
Determine if the series converges or diverges.

Answer
The terms go to zero, and this looks like a ratio test series, so let's use the ratio test:

Since the limit of the ratio of the terms is less than 1, the ratio test says the series converges.
Determine if the series converges or diverges.

Answer
The terms converge to zero. There are many right ways to go from here.
- The series is geometric with r = -0.9. Since |r| < 1, the series converges.
- This is an alternating series whose terms have strictly decreasing magnitudes and are approaching zero. Thus it converges by the AST.
- The ratio test gives us
so the series converges.
Determine if the series converges or diverges.

Answer
The divergence test says that since the terms converge to zero, the series might converge. Again, we have options.
- This is an alternating series whose terms are approaching zero and have strictly decreasing magnitudes. The AST says the series converges.
- We can show that the series of absolute values
converges by either the integral test or the ratio test. Since absolute convergence implies convergence, the original series
converges.
Determine if the series converges or diverges.

Answer
The divergence test says that since the terms approach 0, there's hope for convergence. This isn't an alternating or geometric series. It's awfully messy, so the ratio test doesn't seem like a good idea. The comparison test doesn't sound like a great option either.
The integral test is the only one left, and conveniently the terms of the series have the form

which means they came from the ln function. It looks like the integral test is a good one to try. For positive x, the function

is non-negative and decreasing. We could do lots of work to show this or, easier, just look at a graph. Look at the indefinite integral of f:

Since the integral diverges, the series does too.
Determine if the series converges or diverges.

Answer
The graph of arctan looks like this:

As n approaches ∞, arctan n approaches
. This means

The divergence test says the series diverges.
Determine if the series converges or diverges.

Answer

The denominator seems to have more n factors than the numerator, so maybe this series converges. This looks like a ratio test-able one.
We'll write out the factorial twice because squares of factorials are too complicated:

The ratio test says this series converges.