ACT Math 3.3 Intermediate Algebra
ACT Math: Intermediate Algebra Drill 3, Problem 3. Solve the equation for x.
|ACT Math||Intermediate Algebra|
|ACT Mathematics||Intermediate Algebra|
|Foreign Language||Arabic Subtitled|
|Intermediate Algebra||Systems of equations|
|One-Variable Equations and Inequalities||Solving Equations|
|Product Type||ACT Math|
It's really just a "substitute n' solve" problem.
In the first equation, y is already isolated, so let's just substitute the first equation
into the second.
4 times the quantity 3 halves x plus 4 equals x plus 1.
Multiplying the 4, we get that 12x over 2... or just 6x... plus 16 equals x plus 1.
We combine like terms...so anything with an x goes together and both constants go together.
5x equals negative 15. Divide 5 from both sides, and we get x equals negative 3.
Looks like our answer is B.
As in, "Bad managing decision."