Students

Teachers & SchoolsStudents

Teachers & SchoolsACT Math: Intermediate Algebra Drill 3, Problem 3. Solve the equation for x.

ACT Math | Intermediate Algebra |

ACT Mathematics | Intermediate Algebra |

Foreign Language | Arabic Subtitled Chinese Subtitled Korean Subtitled Spanish Subtitled |

Intermediate Algebra | Systems of equations |

Language | English Language |

One-Variable Equations and Inequalities | Solving Equations |

Product Type | ACT Math |

It's really just a "substitute n' solve" problem.

In the first equation, y is already isolated, so let's just substitute the first equation

into the second.

4 times the quantity 3 halves x plus 4 equals x plus 1.

Multiplying the 4, we get that 12x over 2... or just 6x... plus 16 equals x plus 1.

We combine like terms...so anything with an x goes together and both constants go together.

5x equals negative 15. Divide 5 from both sides, and we get x equals negative 3.

Looks like our answer is B.

As in, "Bad managing decision."