ACT Math 3.5 Intermediate Algebra
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ACT Math Intermediate Algebra Drill 3, Problem 5. Solve this system.
|ACT Math||Intermediate Algebra|
|ACT Mathematics||Intermediate Algebra|
|Algebra||Systems of Equations|
|Foreign Language||Arabic Subtitled|
|Intermediate Algebra||Systems of equations|
|Product Type||ACT Math|
of the two equations.
Elimination is one method of solving equations, so let's try that first.
Multiply the first equation by 2... and we get 6x minus 2y equals 4.
But wait... that looks almost exactly the second equation, except the 4 isn't a 5.
What does that mean?
Well, whenever we see that two equations in standard form have the same coefficients in
front of their variables, we know that these two lines are parallel.
If two lines are parallel, they have no point of intersection... so there is no solution
for this problem.
Looks like E's our answer.
Drive safe, and watch those points of intersection, everyone.