ACT Math: Elementary Algebra Drill 4, Problem 5. What is the solution to the problem shown?
|ACT Math||Elementary Algebra|
|ACT Mathematics||Elementary Algebra|
|Elementary Algebra||Polynomial basic operations|
|Foreign Language||Arabic Subtitled|
|Intermediate Algebra||Roots of polynomials|
|Product Type||ACT Math|
No, not how super-terrific and all-over groovy we happen to be,
but how tidy we are in terms of organizing our brute force methods of multiplying distributions.
Start with just the quantity x minus 1 times the quantity x minus 1.
Follow the arrows and we get x times x which is x squared
x times 1 which is x
... then negative 1 times x, which is negative x.
then negative 1 times 1, which is 1.
Now we just take the quantity x minus 1 and multiply it by the simplified x squared minus 1.
We get x times x squared, which is x cubed and note that since we have a cubed here,
we can eliminate 2 of the potential answers.
Now we've got x squared times negative 1, which is negative x squared,
then negative 1 times x which is negative x,
and finally negative 1 times negative 1 which is positive 1.
So the answer is right here: C.