ACT Math 4.2 Elementary Algebra

ACT Math Elementary Algebra Drill 4, Problem 2. Solve for x.

ACT MathElementary Algebra
ACT MathematicsElementary Algebra
Basic OperationsExponents
Elementary AlgebraSolving linear inequalities with one variable
Foreign LanguageArabic Subtitled
Chinese Subtitled
Korean Subtitled
Spanish Subtitled
Intermediate AlgebraAbsolute value equations and inequalities
LanguageEnglish Language
Product TypeACT Math

Transcript

00:28

We multiply both sides by 2 to get x plus 1 is less than 6.

00:32

Subtract 1 from both sides and we have x is less than 5, so our potential answers are

00:36

only B and C.

00:38

Now let's figure out what this problem would be if x were the most negative it could be.

00:43

What would make things under the absolute value lines to equal NEGATIVE 3?

00:47

We'd have x plus 1 over 2 is less than negative 3, but with no absolute value lines now.

00:53

We multiply both sides by 2 and we have x plus 1 is less than negative 6.

00:57

Then subtract 1 from both sides and we have x is less than negative 7.

01:01

So we have a positive 5 and a negative 7 as the range here.

01:05

Which is... this range... and our answer is C.