ACT Math 4.2 Elementary Algebra

ACT Math Elementary Algebra Drill 4, Problem 2. Solve for x.

ACT Math	Elementary Algebra
ACT Mathematics	Elementary Algebra
Basic Operations	Exponents
Elementary Algebra	Solving linear inequalities with one variable
Foreign Language	Arabic Subtitled Chinese Subtitled Korean Subtitled Spanish Subtitled
Intermediate Algebra	Absolute value equations and inequalities
Language	English Language
Product Type	ACT Math

00:28

We multiply both sides by 2 to get x plus 1 is less than 6.

00:32

Subtract 1 from both sides and we have x is less than 5, so our potential answers are

00:36

only B and C.

00:38

Now let's figure out what this problem would be if x were the most negative it could be.

00:43

What would make things under the absolute value lines to equal NEGATIVE 3?

00:47

We'd have x plus 1 over 2 is less than negative 3, but with no absolute value lines now.

00:53

We multiply both sides by 2 and we have x plus 1 is less than negative 6.

00:57

Then subtract 1 from both sides and we have x is less than negative 7.

01:01

So we have a positive 5 and a negative 7 as the range here.

01:05

Which is... this range... and our answer is C.