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Teachers & SchoolsACT Math: Pre-Algebra Drill 5, Problem 1. Factoring in depreciation, how much is the car worth?

ACT Math | Pre-Algebra |

ACT Mathematics | Pre-Algebra |

Foreign Language | Arabic Subtitled Chinese Subtitled Korean Subtitled Spanish Subtitled |

Language | English Language |

Pre-Algebra | Data collection, representation, and interpretation Percentages |

Product Type | ACT Math |

Ratios, Percentages, and Proportions | Percents |

To get rid of it, we multiply by one over sin squared alpha

The sines squared alpha cancels out on the top and bottom like this

which leaves us with one over cosine squared alpha -1

cosine and secant are inverse functions

so 1 over cosine squared alpha is the same thing

as secant squared alpha and the handy dandy trig identity

1 plus tangent squared alpha equals secant squared alpha

can be rearranged to become secant squared alpha -1

equals tangent squared alpha. What do you know? We're left with secant squared alpha

-1 in our expression

and we just figured out secant squared alpha -1 equals tangent squared alpha.

Which is option E.