ACT Math 5.1 Trigonometry
ACT Math: Trigonometry Drill 5, Problem 1. Simplify the expression.
|Foreign Language||Arabic Subtitled|
|Geometry||Right Triangles and Trigonometry|
|Product Type||ACT Math|
|Trigonometry||Solving trigonometric equations|
To get rid of it, we multiply by one over sin squared alpha
The sines squared alpha cancels out on the top and bottom like this
which leaves us with one over cosine squared alpha -1
cosine and secant are inverse functions
so 1 over cosine squared alpha is the same thing
as secant squared alpha and the handy dandy trig identity
1 plus tangent squared alpha equals secant squared alpha
can be rearranged to become secant squared alpha -1
equals tangent squared alpha. What do you know? We're left with secant squared alpha
-1 in our expression
and we just figured out secant squared alpha -1 equals tangent squared alpha.
Which is option E.