ACT Math: Coordinate Geometry Drill 5, Problem 3. Graph the inequality.
|ACT Math||Coordinate Geometry|
|ACT Mathematics||Coordinate Geometry|
|Coordinate Geometry||Graphing inequalities|
Real number lines and inequalities
|Foreign Language||Arabic Subtitled|
|One-Variable Equations and Inequalities||Graphing on Number Line|
|Product Type||ACT Math|
To isolate x we need to divide both sides by negative 2...
To isolate x we need to divide both sides by negative 2 and… a red light should be
Whenever we divide or multiply an inequality by a negative, we have to flip the sideways
ice cream cone once
around...x is less than or equal to 2.
Well, we have a starting point.
On our number line we mark the 2... and since it's less than OR equal to, it means that
the dot has to be filled in...
So B and C don't work... and neither does A, which starts at 3 rather than 2.
We know that x is LESS than 2, meaning that it's gonna live somewhere
The only one left that might work is D... but just to be sure let's check out the 2nd
part of the equation.
We have negative 2x is less than 6... Divide both sides by negative 2, flip around
the sideways ice cream cone thingy...
...and we have x is greater than negative 3.
So yep, the answer is indeed D.