ACT Math 7.2 Pre-Algebra
ACT Math: Pre-Algebra Drill 7, Problem 2. Solve for x.
One-Variable Equations and Inequalities
|Foreign Language||Arabic Subtitled|
|Pre-Algebra||Linear equations in one variable|
Simple linear equations with one variable
|Product Type||ACT Math|
Lots of simplifyin' to be done here. As we say down on the farm.
Let's start with the distribution part and multiply this 2 here out of the equation.
2 times 3x is 6x, and 2 times negative 6 is negative 12. So now we have 6x minus 12.
Do the same with the negative sign to get rid of the parentheses on the right side,
and we get negative 12 plus 6x... or 6x minus 12.
Both sides of the equation suddenly look uh... strikingly similar.
We have 6x minus 12 on both sides.
If we add 12 to both sides...
...then divide both sides by 6...
...we get "x equals x." What does that mean? Isn't that like the ultimate "duh?"
What it means is that to solve this equation, x can be... literally anything.
Anything real, anyway. Like... it can't be a number divided by zero or the square
root of a negative number or an honest politician...
But we digress. The answer is D.
As in, "Down on the farm."