AP Chemistry 1.1 Forming and Breaking Bonds
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AP Chemistry 1.1 Forming and Breaking Bonds. Find the conjugate base.
AP | AP Chemistry |
AP Chemistry | Forming and Breaking Bonds |
Language | English Language |
Test Prep | AP Chemistry |
Transcript
And here are your potential answers.
Sodium bicarbonate is the active ingredient in baking soda, and it’s what causes bread [People scared of bread expanding from a microwave]
to rise. Or to take over your oven and become some
sort of crazy dough monster. Hypothetically… For this question, we need to consider the [Acid and Base appear at a table]
acid-base chemistry of the bicarbonate ion.
Specifically, we want to know the conjugate base of this species.
Acids and bases react to form their conjugate partners. [Acid and base getting married]
When an acidic species H A reacts with a base B by donating a proton, it becomes its conjugate
base, A-.
On the other hand, when a basic species B reacts with an acid H A by accepting a proton, [Base accepting proton]
it becomes its conjugate acid, HB+.
And then it goes to Starbucks for a pumpkin spice latte. [Base drinking a starbucks latte]
Get it? Basic? Heh.
Anyway, we need to know what happens when bicarbonate acts as an acid, and thus becomes [Bicarbonate jumping on a sofa]
its conjugate base. To act as an acid, it must lose a proton.
Don’t forget that when we split up this ionic species, we have to consider the resulting [Ionic species split in half]
charges.
Our entire bicarbonate species has a -1 charge. Our proton, H+, has a +1 charge.
That means that the CO3 species must have a -2 charge, as the sum of the charge on this
and the proton must equal the overall charge on the entire bicarbonate ion.
So we can see that our conjugate base is CO32-.
So C is the correct answer. And if you understood all that, then you definitely [Girl eating a cake]
deserve some kind of baked good. We recommend cookies, but whatever floats
your boat.