AP Chemistry 1.2 Chemical Reaction Rates
AP Chemistry 1.2 Chemical Reaction Rates. Approximate the appearance rate of ozone.
|AP Chemistry||Chemical Reaction Rates|
|Test Prep||AP Chemistry|
yields 2 O 3 is equal to 0.40 moles per liter per second.
Approximate the appearance rate of ozone.
And here are your potential answers…
All right, so we know the rate at which O2 is disappearing. [Magician makes O2 disappear]
All we need to do is use the stoichiometry of the reaction equation
to find the rate of O3 appearance.
Easy peasy lemon squeezy? [Lemon squeezed on equation]
Alright, well it's not as scary as it sounds…
Using the reaction equation, for every 3 oxygen molecules that disappear, 2 ozone molecules
O2 is disappearing at a rate of 0.40 moles per liter per second.
No, not that kind of mole – the Avogadro’s number kind. [Mole in the ground and Avogadro's constant lands on its head]
Yeah, it’s confusing.
Just don't try shoving a mole into a beaker and you should be okay. [Student holding a mole in a beaker]
Anyway, we can set up a proportion using the stoichiometry and reaction rates to find x,
which represents the unknown rate of O3 appearance.
Which is what the question is asking for, in case you got lost over there in the labyrinth [A couple lost in a maze]
of chemistry and angry moles…
If we multiply both sides of this equation by 0.4 moles per liter per second and crunch
… We find out that the rate of appearance of ozone is 0.27 moles per liter per second.
So B is the correct answer.
Now go take a deep breath and thank a tree for that sweet, sweet O2 . [Girl takes deep breath and hugs a tree]
Seriously, write it a thank you card.
No one ever appreciates all the hard work its doing…[Thank you card by a tree]