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AP Chemistry 3.1 Chemical Reaction Rates 3 Views


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AP Chemistry 3.1 Chemical Reaction Rates. A graph of which of the following data will give a straight line graph for a first order reaction?

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Transcript

00:03

Here’s your Shmoop du jour, brought to you by lines, helping scientists get dates since

00:08

1811. [Boy and girl looking at paintings]

00:09

Because what's dating without a little…chemistry?

00:12

Alright, here’s today’s question:

00:14

A graph of which of the following data will give a straight-line graph for a first order

00:18

reaction?

00:19

And here are your potential answers: All right, so we know that for a first order

00:25

reaction, the rate is proportional to the concentration of the reactant. [First order reaction equation]

00:29

That means that as the reaction proceeds, the concentration of the reactant decreases

00:33

more and more slowly.

00:35

To be a little more specific, the concentration of [A] decays exponentially.

00:40

Just like your concentration in the math class you have right before lunch. [Students in math class]

00:44

If your eyes are in proper working order, you can tell by looking at the graph that

00:47

this is not a straight line. [Graph with a sloping line]

00:49

If it looks like one to you, we highly recommend a quick visit to the optometrist. [Girl conducting an eye-exam]

00:52

Anyway, since this is a graph of the concentration of A versus time, we can eliminate A).

00:58

Options C) and D) could be right if the reaction orders were different.

01:01

But, unfortunately, teachers don’t give credit for potential correctness. [Answers C and D crossed out]

01:05

So that means that a graph of B would give you a straight line for a first order reaction.

01:10

For first-order reactions, the graph of the natural log of the concentration of the reactant

01:15

versus time will be a straight line.

01:18

So B will take you straight to the finish line. [B crossing the finish line on a running track]

01:21

We’d tell you another chemistry pick up line, but all the good ones argon. [Periodic table and Argon asks to call me]

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