# AP Physics 1: 1.1 System Interactions and Changes

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We wouldn't give away the answer to this AP Physics question, not for all the joules in the crown. Come back when you've got some actual jewels. Then we'll talk.

AP Physics 1 | System Interactions and Changes |

Language | English Language |

Science Practice 1 | Using representations and models |

### Transcript

path indicated by the arrow What is the total work

done on the box and hear the potential answers money

jewels Well before we get started it's important to recognize

that we're dealing in physics math here not in real

world situations In math terms If we carry a piano

up two flights of stairs and then back down again

no work has been done on the piano After all

it hasn't had any net movement and the force has

been applied to it has been negated We'll work mathematically

speaking equals force times Displacement and displacement which is represented

by x means a total change in position of an

object Well in our question we think in terms of

direction the boxes moved four meters to the west Five

meters to the north four meters to the east and

another five meters north The four meters east and west

Cancel each other out there's No displacement there because in

terms of lateral movement we end up where we started

so our total displacement is ten meters Now to determine

the force use we use our trusty equation force equals

mass times acceleration because the box is being moved up

The acceleration comes from gravity which is about ten meters

per second squared and since we know the mass of

the boxes two kilograms we can calculate the force Let's

go ahead and plug our numbers into the work equation

Here Work equals twenty newton's times ten meters for a

total of two hundred jewels So option b is the

correct answer Remember no matter how hard we work while

studying in physics terms There's No work being done if 00:01:52.85 --> [endTime] we just stay at our desk