# AP Physics 1: 2.3 System Interactions and Changes

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AP Physics 1: System Interactions and Changes Drill 2, Problem 3. What is the acceleration of the box?

AP Physics 1 | System Interactions and Changes |

Language | English Language |

### Transcript

his surface with a static friction coefficient of zero point

five in a kinetic friction coefficient of zero point two

a force of eighty newtons is applied to the box

What is the acceleration of the box And here the

potential answers in meters per second squared All right well

we here at shmoop love information We crave it but

there is such a thing as too much information For

example one time we told a friend that we still

sleepin batman pajamas And that was definitely a t m

i And this question wealth a little tricky because it

has too much information also but let's tackle the math

First first thing we have to do is get this

box moving And to do that we need to overcome

the force of static friction Well to calculate that force

we just multiply the normal force in this case mass

Times Gravity by the coefficient of friction so here's the

equation Once we have the numbers we need we plug

him in and find that the force of friction is

one hundred newtons Since the force acting on the box

is only eighty new queens the box is going nowhere

fast so the correct answer is just option a zero

meters per second squared and sense is not gonna budge

The kinetic friction coefficient doesn't matter No movement equals no

kinetic friction That's What we mean by t m i