AP Physics 1: 2.3 System Interactions and Changes
Recommendation
Want a study guide too?
AP Physics 1: System Interactions and Changes Drill 2, Problem 3. What is the acceleration of the box?
AP Physics 1 | System Interactions and Changes |
Language | English Language |
Transcript
his surface with a static friction coefficient of zero point
five in a kinetic friction coefficient of zero point two
a force of eighty newtons is applied to the box
What is the acceleration of the box And here the
potential answers in meters per second squared All right well
we here at shmoop love information We crave it but
there is such a thing as too much information For
example one time we told a friend that we still
sleepin batman pajamas And that was definitely a t m
i And this question wealth a little tricky because it
has too much information also but let's tackle the math
First first thing we have to do is get this
box moving And to do that we need to overcome
the force of static friction Well to calculate that force
we just multiply the normal force in this case mass
Times Gravity by the coefficient of friction so here's the
equation Once we have the numbers we need we plug
him in and find that the force of friction is
one hundred newtons Since the force acting on the box
is only eighty new queens the box is going nowhere
fast so the correct answer is just option a zero
meters per second squared and sense is not gonna budge
The kinetic friction coefficient doesn't matter No movement equals no
kinetic friction That's What we mean by t m i