AP Physics 1: 3.1 System Interactions and Changes
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AP Physics 1: 3.1 System Interactions and Changes. What is the coefficient of friction between the biscuit and the court?
AP Physics 1 | System Interactions and Changes |
Language | English Language |
Science Practice 5 | Performing data analysis |
Transcript
end of a narrow lane A grid with various scores
is located at the other end He uses a broom
to push a pot called a biscuit down the lane
If grandpa shmoop gives the four kilogram biscuit an initial
speed of five meters per second and the biscuit comes
to rest after ten meters what is the coefficient of
friction between the biscuit and the court And here the
potential answers All right well this could get complicated if
we let it The biscuit starts off with kinetic energy
and kinetic energy equals one half mass times velocity square
The coefficient of friction then goes to work on the
puck taking that kinetic energy away Well looks like this
is a job for the work energy the're Um the
work energy tour means that the work done by a
force becomes the kinetic energy of the object of forces
working on here's The equation In this case the biscuit
is losing energy so the changing kinetic energy is negative
and the work is negative as well So in our
question here the work done by friction is equal to
the change in kinetic energy Equation For the force of
kinetic friction is mass times gravity times that coefficient And
since we're working here we have to include displacement represented
by x Well now we can solve for the coefficient
you and we can see that as we solve this
equation we don't actually use the objects mass It cancels
itself out Coefficient mu equals velocity squared divided by two
tons Gravity times displacement So when we plug in those
numbers we get an answer of one eighth So option 00:02:02.49 --> [endTime] a Yeah that's it that's the correct answer