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AP Computer Science 2.2 Review of the Basics 184 Views


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AP Computer Science 2.2 Review of the Basics. What is 23 (base 10) in base 2?

Language:
English Language

Transcript

00:00

Sorry Man here's your shmoop du jour Brought to you

00:05

by binary you'll find it a bit useful uncle All

00:12

right what is twenty three Base Ten in based who

00:16

And hear your potential answers So looks like we're being

00:24

asked to convert the base ten number twenty three into

00:27

base to also known as binary while all major modern

00:31

civilizations used base ten numeral system and for good reason

00:35

Over tens of thousands of years we've come to realise

00:37

that ten fingers are really easy to countless when dealing

00:41

with a number higher than ten you just roll over

00:43

into a new set of ten it's about a simple

00:45

is it gets for us computers though think in terms

00:49

of off and on zero and one well that's all

00:52

well and good for counting up to zero in one

00:54

but we're two larger numbers come from and how are

00:57

they stored in a computer's memory Will the answer their

01:00

lives in using lots of zeros and ones zero or

01:04

one in memory is of idiot and with just eight

01:07

bits that are known as one bite you can count

01:11

all the way from zero to two hundred fifty five

01:14

each bit represents a different amount so starting from the

01:18

right side the first bit represents one If that first

01:22

bid is on or one we have a total value

01:25

in our bite of one The next bit over represents

01:29

two but here's where it begins to get oh so

01:31

clever bit after that represents four and the one after

01:35

that ate and after that sixteen and so on using

01:38

the power says too by flipping each differently valued bid

01:42

on or off we can count all the way up

01:44

to two hundred fifty five just add up which bits

01:47

are on and there's your number so this for example

01:50

is one hundred sixty seven right here and here's a

01:55

forty eight and here is two hundred anyway let's count

02:02

twenty three way already know that the fifth bit represent

02:05

sixteen so we'll turn that one on remember binary goes

02:09

from right to left How about the fourth bit representing

02:13

eight right here Eight plus sixteen would leave twenty for

02:16

which is over our target of twenty three so we'll

02:19

leave the fourth bidden as zero The third bit four

02:24

plus sixteen is twenty so yea progress second bit is

02:28

to turn our twenty two and the first bit is

02:32

one so turned that toe one and now when we

02:35

add it all up where twenty three or zero zero

02:38

zero one zero one one one in base too trailing

02:42

zeros can be left off and we're left with one

02:45

zero one one one that's Answer eh Well that was 00:02:51.25 --> [endTime] easy actually Quite difficult No

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