Students

Teachers & SchoolsStudents

Teachers & SchoolsHave plenty of scratch paper on hand before starting one of these problems. We’re not kidding when we say "long" division.

Basic Operations | Multiplication and Division |

Language | English Language |

But wait -- the fairies have happened upon a pile of wild underwear.

Looks like there are 333 pairs of underwear to split evenly among 9 fairies.

Just how many pieces of underwear will each fairy get?

To set up the problem, draw your division box.

The dividend, or what's getting split up, goes inside the box. This is the 333 pairs

of underwear.

For the divisor, think outside the box. This is what you're dividing by.

Next decide if the first digit of the dividend can be divided by the divisor, or if 9 can

go into 3 at least once.

No?

Okay, so now see if 9 will go into the first two digits, or 33? Yes it can!

That means our quotient, or answer, will start above the second digit, or the tens place.

We need to find out "9 times what equals 33".

If you remember your times tables, you'll remember that 9 times 3 = 27, which is close

without going over.

Subtract 27 from 33 and that leaves us with a remainder of 6.

Bring down the last digit and we get 63.

Does 9 go into 63? Why yes it does. How many times?

7 times exactly in fact, which we write above the ones place.

7 times 9 is 63. 63 minus 63 is zero, so we have no remainder.

Yay, our answer is 37 pieces of underwear per fairy!

Even better, there's no remainder so the fairies won't wand-beam each other to death over the

leftover underwear.

That's a terrible way

to go.