SAT Math 11.4 Geometry and Measurement. What is the y-intercept of a line parallel to y – 2x = 4 and passing through the point (1, 2)?

Construction | Parallel Lines |

Coordinate Geometry | Slopes, Parallel and Perpendicular Lines |

Geometry | Coordinate Geometry |

Heart of Algebra | Solving linear equations |

Parallel and Perpendicular Lines | Parallel Lines |

Product Type | SAT Math |

SAT Math | Geometry and Measurement |

So here’s our graph… and we want to figure out where a particular line is.

Well, we’re given the equation y – 2x = 4… but we need to get that thing into standard form.

y has to be all by its lonesome, here on the left… let’s add 2x to both sides.

y = 2x + 4. That's standard form.

If we plug in 0 for y… then x would work out to be -2. So let’s put a point at (-2,0).

If we plug in 0 for x… we get y equals 4. So… another point at (0,4).

And…here’s our line. Looks like for every one unit we move to the right,

we move up 2 units…

…so our slope is 2.

If we draw a parallel line that passes through (1,2)…

…then it will cross the y-intercept… at zero.

Problem solved!

Eh, no. We were thinking maybe just a champagne toast…