SAT Math 8.1 Geometry and Measurement
|Additional Topics in Math||Circle theorems|
Equations of Circles
|Product Type||SAT Math|
|SAT Math||Geometry and Measurement|
Oh, sure… the “bicycle” traveled 2 miles. No one at all was pedaling the dang thing.
Sheesh…credit where credit is due, guys…
All right, what have we got here?
Each tire of our bike has a diameter of 26 inches… well, that should help us find the circumference.
The formula we’re looking for is 2 pi r… or pi times d, because 2r is d.
We already have our d… so...
The perimeter of each tire is 26 pi inches… or 6.8 feet.
If we weren’t already a metric conversion whiz, the problem tells us that one mile equals 5,280 feet…
…so if our bike went TWO miles, then it went 10,560 feet. Which is…a lot of feet.
All right, well… we’ve got our perimeter… now we want to know how many times each tire
can turn that 6.8 feet over the course of its 2-mile run.
We take 10,560 divided by 6.8…
…and get roughly 1,550 rotations.
Now I suppose you’re going to give the bike all the credit for solving this problem, too, aren’t you?