SAT Math 9.5 Algebra and Functions

Algebra | Factoring Quadratic Equations |

Algebra II | Quadratic Equations |

Algebra and Functions | Solving Quadratic Equations by Factoring |

Language | English Language |

Passport to Advanced Math | Quadratic and exponential functions (word problems) |

Product Type | SAT Math |

Quadratic Equations | Quadratic Equations |

SAT Math | Algebra and Functions |

Let’s take a closer look at the second requirement.

This just means that if we plugged the value (x + 1) into the function,

which we’re given in the first requirement, we can solve for x.

To solve this equation, we’re first going to have to turn it back into a polynomial.

So, we expand (x + 1) squared first.

By applying foil, we turn (x + 1) squared into x squared + 2x + 1.

Then, we distribute -6 into the second parentheses. We get -6x - 6.

Now we can combine like terms. There’s only one x squared term, so that stays by itself.

However, we have both 2x and -6x, so we can combine those to -4x.

Then, all of the constants add to +3. Great, we have a polynomial!

To be more specific… it's a quadratic.

We can just stick this puppy into the quadratic formula and come out with the answer.

Plugging in our values, we get that x is equal to 4 plus or minus the square root of 16 – 12 over 2.

This simplifies to 4 plus or minus 2 over 2. The possibilities are 1 or 3.

That's our answer either 1 or 3.