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SAT Math: Identifying the Most Sensible Route to Divide a Polynomial 0 Views


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Description:

If , what is C + D equal to?


Transcript

00:00

Yeah Looks a little something like this We got three

02:16

x plus one plus one over three x minus one

02:19

Alright well after all this work it'd be easy to

02:21

forget what they were asking Like feel what the problem's

02:24

all about anyway We're looking for c plus d and

02:26

they'll be easier to find if we replace nine x

02:28

squared over three x minus one with its quotient Right

02:32

So let's do that C plus de plus one over

02:35

three x minus one sure looks like c plus d

02:38

and three x plus one are best friends So what

02:41

do you think Answer d and a simple hard to

02:43

catch division mistake that could lead to three x minus

02:46

one like in number See Well if you're not a

02:48

huge fan of long division in o who is other

02:51

than a calculator here there's another way to tackle this

02:53

problem But it's kind of error prone to So take

02:55

another quick look at the starting equation We got nine

02:58

x squared over three x minus one equals c plus

03:00

de plus one of three x minus one Well sneaky

03:03

way to create the fraction one over three x minus

03:05

one on the left side of the equation Do this

03:07

not x squared plus one minus one over three ex

03:10

money's one And then we kind of sim fly out

03:12

the ones that we got Nine x squared minus one

03:14

over three x minus one plus one over three x

03:16

minus one walk Adding in subtracting one is the same

03:19

thing is adding zero so it doesn't change the overall

03:22

value of the expression from here Do some quick factoring

03:26

and then i'll get the expression into a form we

03:28

can compare c plus the two and that gets you

03:30

three x plus one times quantity here through x minus

03:34

one over three x minus one plus twenty one over

03:36

three x minus one And then that's what it looks

03:38

like when you simplified terms out Three x plus one

03:41

plus one over three x minus one See we ended

03:44

up in the same position as before Oh and there's

03:46

even a third way to approach this problem If you're

03:48

not asleep yet with plain old algebra just subtract one

03:51

over three x minus one from both sides of the

03:53

equation You know we could have done that That's what

03:55

it would look like and well looks awfully familiar It's

03:58

a bit easier to work with tio Maybe we should

04:00

have started off with this one instead It would've been 00:04:02.635 --> [endTime] a whole lot quicker All right we're done

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