ACT Math: Coordinate Geometry Drill 1, Problem 3. Solve the inequalities and choose the correct graph.
|ACT Math||Coordinate Geometry|
|ACT Mathematics||Coordinate Geometry|
|Coordinate Geometry||Graphing inequalities|
Real number lines and inequalities
The relations between equations and graphs
|Foreign Language||Arabic Subtitled|
|One-Variable Equations and Inequalities||Graphing on Number Line|
|Product Type||ACT Math|
Negative 4 is less than or equal to 2y plus 2.
We subtract 2 from both sides to get:
Negative 6 is less than or equal to 2y.
Then we divide both sides by 2 to get:
Negative 3 is less than or equal to y.
So...let's put this part on the graph...
We start here at negative 3 ... and y is greater than or equal to this number so we're going
to move to the right...
And suddenly, we can eliminate B and D. Note that D has an open circle over negative 3...
...meaning that it's NOT equal to it but only greater than 3.
For our equation, it's greater than or equal... so the answer has to be A, C or E.
OK now consider the second part of the equation separately:
2y plus 2 is less than 8...
Subtract 2 from both sides and we have:
2y is less than 6.
Divide both sides by 2 and y is less than 3.
So let's put this part on the graph - and note that we need the open circle above
positive 3 here because it's not equal to it...
So the area we're talking about is between here and here.
Only A works and that's pretty much it.