ACT Math 1.3 Coordinate Geometry

Negative 4 is less than or equal to 2y plus 2.

We subtract 2 from both sides to get:

Negative 6 is less than or equal to 2y.

Then we divide both sides by 2 to get:

Negative 3 is less than or equal to y.

So...let's put this part on the graph...

We start here at negative 3 ... and y is greater than or equal to this number so we're going

to move to the right...

And suddenly, we can eliminate B and D. Note that D has an open circle over negative 3...

...meaning that it's NOT equal to it but only greater than 3.

For our equation, it's greater than or equal... so the answer has to be A, C or E.

OK now consider the second part of the equation separately:

2y plus 2 is less than 8...

Subtract 2 from both sides and we have:

2y is less than 6.

Divide both sides by 2 and y is less than 3.

So let's put this part on the graph - and note that we need the open circle above

positive 3 here because it's not equal to it...

So the area we're talking about is between here and here.

Only A works and that's pretty much it.