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ACT Aspire Math Videos 91 videos

ACT Aspire Math: Solving for x when It's in the Denominator
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ACT Aspire Math: Identifying the Graph of a Reflected Line 6 Views


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Description:

The graph of y = -x + 5 is reflected across the x-axis.

Which of the following shows the reflected graph?


Transcript

00:03

Okay Shmoop math people Here we go A graft coming

00:06

at you The graph of y equals negative X plus

00:08

five is reflected across the x axis Which of the

00:12

following shows the reflected graph Okay do we need to

00:19

get out our handy dandy pocket mirror for this problem

00:22

We advise against it since to see the reflection from

00:24

the right angle you'd probably have to smash your face

00:27

up against your desk Instead let's consider what rules we

00:30

know about transform ations But when we reflect a point

00:32

across the x axis we multiply the original y coordinate

00:36

by negative one Find a new why co ordinate while

00:38

the x coordinate remains unchanged In other words the rule

00:41

to remember about reflecting across the x axis is that

00:45

the point x why would be transformed into the point

00:48

x negative y very important concept here were given a

00:52

line and an equation for that line No why calls

00:54

they could expose five rather than a set of points

00:57

However we can imagine that line is having many different

01:00

points on it in reflecting those many different points across

01:03

the x axis We know that for each point will

01:06

retain the same x values but corresponding why values should

01:10

be multiplied by negative one Right So our new equation

01:13

then will demonstrate those new negative y values right there

01:16

multiplied by negative one So we get negative y equals

01:19

negative x plus five Well to graft this equation no

01:22

we just put it into slope intercept form y equals

01:24

mx plus b That means we'll need to multiply both

01:27

sides by negative one so we can isolate that Why

01:29

there And we get y equals negative The quantity there

01:32

of negative exposed five or y equals x minus five

01:36

So the reflected graph corresponds to the equation Y equals 00:01:40.281 --> [endTime] x minus five and that's pretty much it

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