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AP Chem 1.3 Laws of Thermodynamics 17 Views


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Description:

AP Chem 1.3 Laws of Thermodynamics. How much energy would be required to change the temperature of 200 g of aluminum as described in the video?

Language:
English Language

Transcript

00:04

Here’s your Shmoop du jour, brought to you by aluminum. [Plane in the sky]

00:07

From airplane wings to surgical instruments, aluminum is useful in many ways…

00:12

…. but soda cans still take the cake for us. [Guy drinking soda on a plane]

00:15

Ah.

00:16

Refreshing. [Guy chucks the can away]

00:17

Here’s our question:

00:18

Aluminum is a metal and a key raw material.

00:20

It is used to makes soda cans, foil, and even airplanes.

00:24

How much energy would be required to change the temperature of 200.0 g of aluminum from [The question being written out]

00:30

10.0 °C to 25.0 °C?

00:33

The specific heat of aluminum is 0.902 J/g °C.

00:39

And here are the potential answers, alright a bunch of joules [The answers appear]

00:44

Alright, lets see (glug, glug, glug) ahhh, seventh can today.

00:48

Okay, now that we’re all sufficiently hydrated, let’s get down to defeat the Huns… [Man has his fists up]

00:52

…uh. [Guy looks confused]

00:53

Sorry, we meant "to defeat this problem."

00:55

We're always getting chemistry and Mulan confused. [People in a chemsitry lab]

00:58

To solve today’s calorimetry question, we need to use this equation which relates [Teacher writing on a blackboard]

01:04

the amount of heat or energy transferred, Q, with a material’s mass, m, heat capacity,

01:11

C, and change in temperature, delta T. Phew.

01:14

That was a mouthful.

01:17

Quick, someone give us an eighth can of soda so we can rehydrate. [Guy drinking another can of soda with a pile of empties behind him]

01:19

Ah, much better.

01:20

So we’re trying to find Q, the amount of heat or energy transferred into the aluminum [Guy collapses onto the floor]

01:24

to heat it up.

01:25

From the problem statement, we know that the mass of aluminum that is heated is 200g

01:29

We also know that the specific heat is 0.902 joules per gram per degree

01:33

Celsius.

01:34

Finally, we know the aluminum is heated from 10 °C to 25 °C, which means a change [The equation working is written on the blackboard]

01:39

in temperature is 15 °C.

01:41

If we multiply this all out, we find that Q is 2,706 joules.

01:46

Rounding down to 2,700, this is answer choice (D).

01:50

What better way to celebrate our success than with a delicious can of soda? [Guy drinking soda on a plane again]

01:52

Ugh, that one was kind of sickening. …and why are our teeth suddenly falling

01:56

out? [Guy is crying]

01:57

Only one thing to do.

01:58

Relax, crack open another can. [Guy smiles and some of his teeth have fallen out]

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